3x^2+20=14

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Solution for 3x^2+20=14 equation: 



3x^2+20=14

We move all terms to the left:

3x^2+20-(14)=0

We add all the numbers together, and all the variables

3x^2+6=0

a = 3; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·3·6
Δ = -72
Delta is less than zero, so there is no solution for the equation

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